Volume Occupied By 1 Molecule Of Water Is. 1 mole of water = 6.022 x 10^23 molecules of water, so 55.5 moles of water = 55.5 x 6.022 x 10^23 = 3.34 x 10^25 molecules of water. The gram molecular mass of water is 18.02.
= 3 x 10⁻²³ cm³. 1cm 3=1gm of h 2 o= 181 mol of h 2 o= 181 ×6×10 23 molecules of h 2 o⇒1cm 3 has 31 ×10 23 molecules of h 2 o∴ volume of 1 molecule of h 2 o= 31 ×10 231 cm 3=3×10 −23cm 3hence, the correct option is a. So, the volume of 1 molecule of water = 18/ (6.023 × 10 − 23) volume of 1 molecule of water = 3.0 × 10 − 23 cc.
1 G Water= 1/18 Moles Of Water.
Where n is avogadro number. ∴ molar volume (vm) = m/ρ. Volume of 1 molecule of water = 18/ (6.022 × 10 23) volume of 1.
Vm = 18 Cm 3 /Mol.
Where n a is avogadro number. 1 mole of water = 6.022 x 10^23 molecules of water, so 55.5 moles of water = 55.5 x 6.022 x 10^23 = 3.34 x 10^25 molecules of water. Volume occupied by one molecule of water is?
Where N A Is Avogadro Number.
(at wt of h *2 + at wt of oxygen = 18) volume occupied by 1 molecules of water = (18 / (6.02 x 10²³)) cm³. Hence, the correct option is (d). ∴ molar volume (v m) = m/ρ.
Molar Mass Of Water = 18 G / Mol.
=1 gram/ 1 gram cm⁻³ = 1 cm³. 1cm 3=1gm of h 2 o= 181 mol of h 2 o= 181 ×6×10 23 molecules of h 2 o⇒1cm 3 has 31 ×10 23 molecules of h 2 o∴ volume of 1 molecule of h 2 o= 31 ×10 231 cm 3=3×10 −23cm 3hence, the correct option is a. 3.34 x 10 25 molecules of water = 1 litre,
The Gram Molecular Mass Of Water Is 18.02.
V m = 18 cm 3 /mol. Molar mass of water (m) = 18 g/mol. Therefore, volume of 1 molecule of water = v m /n.
